Date: Wed Oct 30 20:19:05 PST 2002
Student's Name: Tyler
Answer(or question to Mentor): Hey Angela,
It took me a long time to figure it out but I think that I finally got it! What I think part A's answer is, is 9ft. Why? Well, first I changed all of the fractions (1/4, 1/3, and 3/4) into 12ths. 1/4=3/12 1/3=4/12 3/4=9/12 Well, 3/12 of the stilt was under the ground and that means that 9/12 was out in the open. Well in 2000, 4/12 of the open stilt was covered with water. That was leaving 5/12 of it dry. Well, it says that 5ft was left dry so I am assuming that 1/12 is equal to 1 foot. In 2002, the storm covered 9/12 of the open stilt. When you add what was under the groung and what was under the water it turns out to be 12/12. Which is all of it. There is no room for any more water. So, since i said that 1 ft is equal to 1/12 then that means that 9/12 is equal to 9 feet. which is what I think the answer is to part A.
On bart B i think that the answer is none. Because I said earlier that after those 9 feet were covered that there was no more room to put anything else. So, there is NO room left.
Well i have figured out the challenge problem but it is late and I will try to get it to you tomorrow. Ok well send back soon ok ttyl!
Tyler
Date: Thu Oct 31 09:22:31 PST 2002
Student's Name: Tyler
Answer(or question to Mentor): hey again,
Ok i have the answer to the challenge problem! I think that the answer is yes, his hose woud get washed away. Bob says that 40% of the stilt is under the ground. I measured that and that is 4/10 or in 12ths I think that it is 3.5/12. Then he only has 8.5 of the stilt left. The storm surge of 2002 goes 9 ft up so he needs .5 more stilt if he does not want his house washed away. So, yes hi house would get washed away!
please please write back soon, i really want to know if i get this right! I have worked hard!!!!!!!!!!!
so i guess i will ttyl chow
Tyler
Date: Thu Oct 31 17:14:46 PST 2002
Student's Name: Tyler
Mentor Reply: Tyler-
Thank you for explaining so clearly how you solved the problem. I like that you found a common denominator for the fractions. You were on the right track, but the answer was not correct.
In your solution, you said that 9/12 of the stilt was out in the open. Notice that the 1/3 in the problem refers to 1/3 of the 9/12 of the open stilt, not of the whole stilt. Therefore, only 3/12 of the open stilt was covered with water. When you figure out the solution, part B and the challenge problem will change as well. I look forward to your revision.
-Angela
Date: Fri Nov 1 13:29:19 PST 2002
Student's Name: Tyler
Instructor Comments: Angela,
Terrific. I like the way you used her description of the "open stilt."
Dr. Bowers
Date: Fri Nov 1 16:02:58 PST 2002
Student's Name: Tyler
Mentor Reply: Tyler-
Thank you for explaining so clearly how you solved the problem. I like that you found a common denominator for the fractions. You were on the right track, but the answer was not correct.
In your solution, you said that 9/12 of the stilt was out in the open. Notice that the 1/3 in the problem refers to 1/3 of the 9/12 of the open stilt, not of the whole stilt. Therefore, only 3/12 of the open stilt was covered with water. When you figure out the solution, part B and the challenge problem will change as well. I look forward to your revision.
-Angela
Date: Wed Nov 6 18:11:08 PST 2002
Student's Name: Tyler
Answer(or question to Mentor): Ok well i thought about it and now i have a question. I made my paper into the stilt. I did not do any of this physically, just on the paper. I put 1/4 of it under the ground. Then, I put 1/3 of the stilt that was out of the ground under water. So now I have it with 1/3 of ¾ under the water. Then what was left over was 5 ft. Now I split the 2/3 of the outside stilt into 6 pieces. Making each little piece a 9th. And now I think that 1/9 of 1/3 = a foot. Am I right about that? Well when I try to get to count up the feet that the storm surge covered then it comes up as 9/18. So now I split all of the 9th s into 18ths. That leaves 14/18 dry and 6/18 0r 3/9 wet. So I think that 3 ft of was dry in 2000. Now in 2002, I put in 18ths also. Then I tried to get ¾ of 18 but it came out to be 13 and a 1/2. that can not be in feet. It wont come out evenly. So I was wondering if you could tell me what I am doing wrong with this part. It is wery confusing. Thanx for all of your help. But I need more!!!!!!!!!!! LOL! Ok so send back soon as possible PLEASE!
Tyler
Date: Thu Nov 7 21:46:23 PST 2002
Student's Name: Tyler
Mentor Reply: Tyler-
The answer to part A is 5 5/8 feet and the answer to part B is 1 7/8 feet. You were so close, but I think the problem came when you split the 2/3 into 6 pieces. Before that, everything was good. I like that you made your paper into the stilt. That was a good idea. Good luck on the next problem.
-Angela
Date: Tue Nov 12 20:44:38 PST 2002
Student's Name: Tyler
Answer(or question to Mentor): Thanks,
I think that I understand this one a little better then I did the last one.
1. Ok, well I think that the answer to the 1st part was 330. What I did was I did 9x14 because each of the 9 grams of fat has 14 calories. Well out of that I got 126. Then I did 4x36 because there are 4 calories in each of the 36 carbohydrates. Then I got 144. Then I did 15x4 because each of the 15 grams of protein there were 4 calories in each one. Of that I got 60. Then I added them all together and got 330 calories.
2. Ok on this one I put 330 over 2000 because 2000 is all of RDA. Then she has taken 330 of it. So when I simplified it all I could I got 33/200. So I was trying to get it to the presentage of 100 so I just chopped 33 in half and it was 16.5% of 100. That is what I think that the answer is.
3. Ok for this one I put 14% because 100% is the whole thing and it says that 14 was fat. So I just put it as 14%. I was not so sure about that one because it seemed to easy so there must be something else to it.
Challenge:
Ok on the challenge I got that there were 36 nuggets in the beginning. Well I first split the whole bucket into 3 pieces and took away one of them. That was what Ralph ate, 1/3. Then of that Juan ate ¾ of it. Which means he ate ½ of the whole thing. Then he passed it to Miles who ate half of what the other’s did not eat. Then that left 1/12 left over. Then there were 3 nuggets left. So I think that 1/12 of the bucket is equal to 3 nuggets. An easier way to do it is to just multiply all of the fractions. Like this- 1/3 x3/4 x1/2. When you multiply all of that you get 1/12 also. So if 1/12 is equal to 3 nuggets then you just multiply 12x3 and you get your answer!!!!!!!!!!!!!
Thanks for taking your time to help me with this. I really appreciate it!!!
Your Friend
Tyler
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Date: Tue Nov 19 20:25:58 PST 2002
Student's Name: Tyler
Mentor Reply: Tyler-
Great job explaining your work. You got the correct answers of 330 calories for part 1, 16.5% for part 2, and 36 for the challenge problem. However, part 3 was incorrect. Keep in mind that the 14 grams of fat was 14 grams of the total grams in the cheeseburger. I look forward to your revision. Also, since you got the challenge problem, I would like you to try another one. Here it is:
A man competing on a game show ran into a losing streak. First, he bet 1/2 of his money on one question and lost it. Then he lost 1/2 of his remaining money on another question. Then he lost $300 on another question. Then he lost 1/2 of his remaining money on another question. Finally, he got a question right and won $200. At this point, the show ended and he had $1200 left. How much did have before his losing streak began? Good luck!
-Angela
Date: Wed Nov 20 12:45:22 PST 2002
Student's Name: Tyler
Instructor Comments: Angela,
Great job! I love the new challenge problem.--Dr. Bowers
Date: Thu Nov 21 07:16:59 PST 2002
Student's Name: Tyler
Mentor Reply: Tyler-
Great job explaining your work. You got the correct answers of 330 calories for part 1, 16.5% for part 2, and 36 for the challenge problem. However, part 3 was incorrect. Keep in mind that the 14 grams of fat was 14 grams of the total grams in the cheeseburger. I look forward to your revision. Also, since you got the challenge problem, I would like you to try another one. Here it is:
A man competing on a game show ran into a losing streak. First, he bet 1/2 of his money on one question and lost it. Then he lost 1/2 of his remaining money on another question. Then he lost $300 on another question. Then he lost 1/2 of his remaining money on another question. Finally, he got a question right and won $200. At this point, the show ended and he had $1200 left. How much did have before his losing streak began? Good luck!
-Angela
