Date: Wed Oct 30 05:40:18 PST 2002
Student's Name: M.T.
Answer(or question to Mentor): I drew a pole / graph and divided it into four sections, all equal. The
first forth was underground; I got two ½ feet. The next forth was under
water and I got two ½ feet. The next two fourths (a half) was above
water; I got five feet.
A Answer: 5.625 feet of the pole were under water.
Rationale: I drew another pole/ graph and divided it into five parts
(not all equal). In the first part, was a forth (2 ½ feet) Then I
divided the remanding (7 ½ feet) into fourths because ¾ was covered in
water. I got 1.875 feet and I multiplied it by three because I need to
know how much of the pole was covered by water. My final answer is
5.625. The first pole/ graph helped me figure out how much of the pole
was underground.
B Answer: 1.875 feet of the pole was above water in 2002.
Rationale: 1.875 feet was left dry in 2002 because 5.625 feet subtracted
from 7.5 feet is 1.875 feet. 5.625 feet is the amount of the pole
covered by water. The 7.5 feet is the length of the pole not including
the first two ½ feet underground. If you subtract 5.625 feet from 7.5
feet, you would get how much of the pole was dry. 1.875 feet of the pole
was dry.
Date: Thu Oct 31 14:31:09 PST 2002
Student's Name: M.T.
Mentor Reply: M.T.- I couldn't have said it better myself. You did a wonderful job of solving the problem as well as submitting a thorough explaination of how you did it. Now see if you can do the same for the second question. Good luck and feel free to ask questions if you have any. Happy Halloween!
Todd
Date: Sat Nov 2 23:31:01 PST 2002
Student's Name: M.T.
Instructor Comments:
Todd,
I agree, this is a wonderful answer and explanation. Plese nominate it to be posted. Your response is perfect as well. Submnit as is.
Dr. Bowers
Date: Tue Nov 5 17:21:10 PST 2002
Student's Name: M.T.
Answer(or question to Mentor): Challenge: No, Andy's house did not float away because there was 0.375 feet of the pole was left dry.
Rationale: I drew a pole and divided it into 10 sections. I labeled each line 10, 20, 30, 40, 50 and so on. I colored four sections because 40% of the pole was underground. Now I have 60% of the pole left. I already knew that the pole is ten feet so I found out that 40% of the pole is 4 feet by multiplying 10 by 0.4. I have 6 feet left above ground and 5.625 feet of the pole is covered by water. I know this because of the first problem. Next, I subtracted 6.000 by 5.625 and got 0.375. This means that 0.375 feet of the pole was dry, so Andy’s house could not have floated away.
~ M.T.
Date: Wed Nov 6 06:21:46 PST 2002
Student's Name: M.T.
Mentor Reply: M.T.- I couldn't have said it better myself. You did a wonderful job of solving the problem as well as submitting a thorough explaination of how you did it. Now see if you can do the same for the second question. Good luck and feel free to ask questions if you have any. Happy Halloween!
Todd
Date: Wed Nov 6 06:23:13 PST 2002
Student's Name: M.T.
Mentor Reply: I think that both of this student's reponses should be nominated. This kid knows what's going on!
Todd
Date: Wed Nov 6 15:26:08 PST 2002
Student's Name: M.T.
Answer(or question to Mentor): Thank You!
Date: Thu Nov 7 16:09:15 PST 2002
Student's Name: M.T.
Answer(or question to Mentor): Todd, I am a little confused with your response to the challenge answer, since it is the exact same response as the first one.
~M.T.
Date: Tue Nov 12 18:52:37 PST 2002
Student's Name: M.T.
Answer(or question to Mentor): 1.Answer: Charle has 33/100 of her intake for the day ingested.
Rationale: I Read the problem twice to make sure I understood. Then I multiplied 14 by 9 because 1 gram of fat equals 9 calories and I got 126. Then I multiplied 36 by 4 because there are 4 calories in 1 carbohydrate and I got 144. Then I multiplied 15 by 4 and because there are 4 grams of fat in 1 gram of protein and I got 60. Then I added what I got for my answers together and I got 330. I put 330/2000 and then I simplified. After I simplified the first time I got 165/500. Then I simplified again and got 33/100. Charle has eaten 33/100 of her intake in calories.
2. Answer: 3/13 of the cheeseburger is fat.
Rationale: I do not get how to do this part but I will try. I added 14, 36, and 15 to get 65. Then I put 15/65. Then I simplified that to 3/13 of the cheeseburger is fat.
~MT
PS this is the answer for November 11th-15th
Date: Tue Nov 12 19:05:27 PST 2002
Student's Name: M.T.
Answer(or question to Mentor):
Challenge
Answer: Lani bought 36 McNuggets.
Rationale: First I converted the first fraction into 12ths. Then I found out that 1/3 is equal to 4/12. What is left of the Mcnuggets is 8/12. Then I found out that ¾ of 8/12 is 6/12, I found this out by making 8 the whole. ¾ of 8 is 6/12 so I subtracted 6/12 from 8/12. I got 2/12. Then I found half of 2/12 by simply knowing that is there are 2/12 half would be 1/12. There was 1/12 of the original number of McNuggets left when Lani got them back. When the McNuggets made their way back to her there were 3 left. If you multiply 3 by 12 you get 36. Therefore, Lani bought 36 Mcnuggets to start with.
~MT
Date: Tue Nov 12 19:05:51 PST 2002
Student's Name: M.T.
Answer(or question to Mentor): I think that my screen might be a little messed up so i am answering to the November 11th-15th week problem.
Date: Mon Nov 18 20:14:57 PST 2002
Student's Name: M.T.
Answer(or question to Mentor): Can you read my text because I can’t read yours, if you have posted a conclusion.
~M.T.
Date: Tue Nov 19 10:47:30 PST 2002
Student's Name: M.T.
Mentor Reply: M.T. - Your explaination of the problem is wonderful. Thank you for doing such elaborate work. With you showing your work I am able to follow each step and possibly correct any problems you might of had. However, you did not have any problems in your solution. Good job and keep up the good work.
Todd
Date: Tue Nov 19 14:21:36 PST 2002
Student's Name: M.T.
Mentor Reply: M.T. - Once again, a wonderful job of explaining your work. By doing this you have allowed me to pick up on a problem you had during the cheeseburger problem. All of your numbers for the calories are correct, however, you need to go back and check your simplified answers. Resubmit these answers to me as soon as possible. Keep up the good work.
Todd
Date: Wed Nov 20 23:19:00 PST 2002
Student's Name: M.T.
Instructor Comments: Todd, Fine. make sure that MT knows that both answers are incorrect, but that his challenge solution is correct and well explained.--Dr. Bowers
