Date: Wed Oct 30 18:34:50 PST 2002
Student's Name: Kevin Answer(or question to Mentor): Problem Solution: A. 5.625 feet
B. 1.875 feet
Problem Rationale:
A. If ¼ of the pole was buried, then ¾ of the pole was exposed. Of the exposed pole, 1/3 was covered in 2000 by the storm surge, leaving 5 feet dry. If 5 feet=2/3 of the exposed pole, then 1/3 of the exposed pole = 2.5 feet. So 5 feet + 2.5 feet = 7.5 feet of exposed pole. To find out how much of the exposed pole was covered in 2002, I multiplied the amount of the exposed pole, 7.5 feet, by ¾ (75%), which equaled 5.625 feet.
B. Since the exposed pole = 7.5 feet, I subtracted the covered amount, 5.625 feet, from the total exposed amount of 7.5 feet, which equaled 1.875 feet.
Challenge Solution: No, his house was not washed away.
Challenge Rationale: Since Andy and Bob have the same size poles, I can use the information about Andy’s pole to figure out the original size of both poles. The exposed part of Andy’s pole is ¾ of the total length. I know that ¾ of the total length is 7.5 feet. If total length is “X”, then ¾ * X = 7.5 feet. If I divide 7.5 feet by ¾, this equals 10 feet, the total original size of the pole.
Since the total length of Bob’s pole was 10 feet and 40%, or 4 feet, was buried underground, then 6 feet was left exposed. Since the storm surge in 2002 was only 5.625 feet, I know that there was 0.485 feet left until the poles were completely covered by subtracting 5.625 feet from the 6 feet of the exposed pole.
Date: Sat Nov 2 22:15:53 PST 2002
Student's Name: Kevin Instructor Comments: Nhia,
I am not sure why you didn’t' respond to this student. His explanation is a pleasure to read. I don’t 'think I could have written a better one.
Please respond by saying, "Kevin, Congratulations! Your answers are all correct and your explanation is outstanding. Thank you for clarifying each step carefully. Your answer will be posted in the problem highlights next week."
Dr. Bowers
Date: Sun Nov 3 20:35:07 PST 2002
Student's Name: Kevin Mentor Reply: Hi Kevin,
Congratulations! Your answers are all correct and your explanation is outstanding. Thank you for clarifying each step carefully. Your answer will be posted in the problem highlights next week.
Nhia
Date: Tue Nov 5 17:54:40 PST 2002
Student's Name: Kevin Mentor Reply: Kevin, Congratulations! Your answers are all correct and your explanation is outstanding. Thank you for clarifying each step carefully. Your answer will be posted in the problem highlights next week
Nhia
Date: Tue Nov 5 18:13:43 PST 2002
Student's Name: Kevin Mentor Reply: Dr. Bowers,
I did respond to Kevin. I don't know why didn't post. I just found out when I received your feedback. I wrote to him what you suggested, but today I went back to check again and I noticed that my submission to him didn't post either. When I first submitted to him it posted on my computer screen, but on the top box where says, " number of Mentor Submissions" was zero. I didn't think that would be a problem. And now is a problem. I thought you should know. I just e-mail him again. I hope it worked this time.
Nhia
Date: Wed Nov 6 12:10:50 PST 2002
Student's Name: Kevin Instructor Comments: Nhia,
Your first response did not post, but your second two did post. I cannot figure out why it didn't work the first time, but it worked both times after my comment to you. In fact, I even logged on using Kevin's code to see what he saw and he saw two copies of that response. So, all is fine. Please bring a copy of this so that we can add it to the highlight list.
Dr. Bowers
Date: Tue Nov 19 15:33:58 PST 2002
Student's Name: Kevin Answer(or question to Mentor): Problem Solution: 1.The burger has 16.5% of the recommended allowance.
2. 38.8% of the burger is fat.
Problem Rationale: 1. Since 1g of fat=9 calories then you would multiply the number of grams of fat (14) by the number of calories per gram (9), which would equal 126 calories from fat. Since 1g of carbohydrates=4 calories then you would multiply the number of grams of carbohydrates (36) by the number of calories per gram (4), which would equal 144 calories from carbohydrates. Since 1g of protein=4 calories then you would multiply the number of grams of protein (15) by the number of calories per gram (4), which would equal 60 calories from protein. You then add the calories (126+144+60), which equals 330 calories. To find the percentage of recommended allowance of calories in a cheeseburger, you divide 330 by 2000.
2. To find the percentage of fat, I took the calories from fat (126) and divided them by the total calories (330)= 38.18181818…%
Challenge Solution: 36 Chicken McNuggets.
Challenge Rationale: Let X = the total # of McNuggets bought. After Ralph ate his portion (1/3 of the bucket), there was 2/3 of the bucket left, or 2/3 * X. After Juan ate his portion (3/4 of the amount received from Ralph), that left ¼ of the amount received from Ralph, or ¼ * 2/3 *X. After Miles ate his portion (1/2 of the amount received from Juan), that left ½ of the amount received from Juan, or ½ * ¼ * 2/3 * X. I know the amount left after Miles ate was 3 McNuggets, so I know 3 = ½ * ¼ * 2/3 * X. Next I need to multiply all the fractions, ½ * ¼ * 2/3 = 2/24 or 1/12. Then I know 3 McNuggets = 1/12 * X. To solve for X, I multiply both sides of the equation by 12, so 12/12 * X = 3 *12, or X = 36 McNuggets.
Date: Wed Nov 20 18:13:52 PST 2002
Student's Name: Kevin Mentor Reply: Kevin,
Congratulations! Your answers are all correct and your explanation is outstanding. Thank you for clarifying each step carefully. Your answer will be posted again in the problem highlights next week.
Date: Wed Nov 20 22:46:15 PST 2002
Student's Name: Kevin Instructor Comments: Nhia,
I agree, this should be posted. Good. Why don’t you challenge him by writing a problem that involves both addition and fractional multiplication such as the mint problem we did in class? --Dr. Bowers
Date: Thu Nov 21 14:04:29 PST 2002
Student's Name: Kevin Mentor Reply: Hi Kevin,
Congratulations! Your answers are all correct and your explanation is outstanding. Thank you for clarifying each step carefully. Your answer will be posted again in the problem highlights next week.
Nhia
