Date: Thu Oct 31 15:17:08 PST 2002
Student's Name: Olivia
Mentor Reply: Hi Olivia, I am looking forward to reading your response.
Lillian
Date: Sat Nov 2 21:02:55 PST 2002
Student's Name: Olivia
Instructor Comments: Lillian,
This is fine. When you respond, can you please write "DR. BOWERS--- PLEASE CHECK-- FIRST RESPONSE" This will ensure that I read it as soon as possible so that you can get it out to the student as soon as possible. The system does not distinguish between first and second responses when it emails me, so this is the only "fix" that I can use to get around the bug. Thank you,
Dr. Bowers
Date: Mon Nov 4 13:01:22 PST 2002
Student's Name: Olivia
Mentor Reply: Hi Olivia, I am looking forward to reading your response.
Lillian
Date: Mon Nov 4 14:12:14 PST 2002
Student's Name: Olivia
Answer(or question to Mentor): say that the fouth is 100% and if you have a third of the percent than you would have 75% percent of the stilt sticking out of the ground. the answer to question 1 is um.....it's....um...the strm surge was um... 3/4% high. Anyway the answer to question 2 is 5ft of it dry because it says so in the problem. well i hope it's right! Bye lillian!
Date: Fri Nov 8 19:44:32 PST 2002
Student's Name: Olivia
Mentor Reply: Hi Olivia, thank you for attempting this problem.
The answer to the first question is 5.625 feet high. To get this answer, first you need to consider that in 2000 the storm surge covered 1/3 of the stilt leaving 5 feet (or 2/3 of the stilt) dry. Therefore, each 1/3 of the stilt above the ground is equal to 2.5 feet. Since the part of the stilt that is above ground consists of three sections (of 1/3), you need to multiply 2.5 times 3. This gives you that the part of the stilt above ground is equal to 7.5 feet. The 7.5 feet represent only 3/4 of the total height of the stilt because 1/4 of the stilt is under ground. Therefore, the remaining 1/4 of the stilt below the ground is 2.5 feet. This means that the total height of the stilt is 10 feet because when you add 7.5 (3/4 of the stilt above ground) + 2.5 (1/4 of the stilt below ground) you get 10 feet.
Now consider that the 2002 storm surge covered 3/4 of the stilt above ground, which is equal to 7.5 feet in height. Therefore, you need to multiply 3/4 times 7.5 feet, which gives you an answer of 5.625 feet. This means that in 2002 the storm surge is 5.625 feet high.
The answer to the second question is 1.875 feet. To get this answer, you subtract 5.625 feet (height of 2002 storm surge) from 7.5 feet (height of the stilt above the ground).
The answer to the challenge problem is that Bob’s house did not get washed away because the storm surge is 0.375 feet lower than the height of the stilt. To answer this problem, you need to consider that Bob constructed his house so that 40% of each stilt was stuck in the ground. Since Bob’s stilts were of the same length as Andy’s, this means they are each 10 feet long. Consider that 10 feet equals 100% of the stilt. Therefore, the 40% of the stilt stuck in the ground is equal to 4 feet. This means that the part of the stilt above ground is 60% or 6 feet in height. Since the 2002 storm surge was only 5.625 feet high, Bob’s house was not washed away because the storm surge was 0.375 feet below the height of the stilt.
Thank you for your effort in trying this problem.
Lillian
Date: Mon Nov 11 18:54:52 PST 2002
Student's Name: Olivia
Answer(or question to Mentor): hey lillian... well that was ALOT of writing. but i kind-of see where i was wrong and kind-of see where i was right but i have to go now...so i will talk to you later. Bye.
Date: Mon Nov 18 15:21:35 PST 2002
Student's Name: Olivia
Answer(or question to Mentor): well a cheeseburger has 14 g. of fat, 36 g. of carbs., and 15 g. of protein. one gram of fat is nine calories. 1 gram of carbs is 4 calories. 1 gram of protein is 4 calories.
SO IF HAD14 gms of faT, THEN I WOULD TIMES IT BY NINE AND GET 126. IF I HAD 36 GMS. OF CARBS THEN I WOULD TIMES IT BY 4 AND GET 144. IF I HAD 15 GMS. OF PROTEIN THEN I WOULD TIMES IT BY 4 AND GET 60. IF I ADDED ALL THOSE UP, I WOULD GET 330. SO THE ANSWER TO QUESTION ONE IS 330 CALORIES. THE ANSWER TO Q 2: IS 6.20 BECAUSE I DIVIDED 330 INTO 2000, AND GOT 6 WITH A REMAINDER OF 20 SO I GOT 6.20. THE ANSWER TO qUESTION 3: IS 23.8%. I GOT THIS BECUASE I DIVIDED 14 INTO 330 AND GOT 23 WITH A REMAINDER OF 8 SO IT IS 23.8. WELL,
C-YA!
Date: Tue Nov 19 14:55:40 PST 2002
Student's Name: Olivia
Mentor Reply: Hi Olivia, thank your submitting a response. Your answer of 330 calories is correct and your explanation is very clear.
Your answer of 6.20 is incorrect. Can you please state what the fraction Charle has now injested out of her daily allowance (RDA)?
Your answer of 23.8% is incorrect. Can you please explain why you divided 14 into 330?
I am looking forward to reading your response.
Lillian
Date: Wed Nov 20 21:09:39 PST 2002
Student's Name: Olivia
Instructor Comments: Lillian,
I think you can be a bit more helpful than saying, 'Can you please state what the fraction Charle has now injested out of her daily allowance (RDA)?' I am not sure that sentence makes sense anyway--and there is a typo (injested should be ingested). The point is, she simply inverted the fraction but we would like to tell her in a way that isn't merely stating a procedural comment such as 'invert the fraction.' How does something like this sound: The process you used in converting grams to calories is correct. However, the second part, note that when you calculated 2000/330, you got an answer of 6.2, which is greater than 1. This means that the numerator is larger than the denominator which, in this case, would mean that the amount is more than 1. This would mean that she ingested more calories eating one cheeseburger than the RDA for the entire day! This is not actually what happened. In fact, what fraction of the 2000 calories allowed per day did she eat?'
The same applies for the second answer. Instead of just saying it is wrong, let her know what she has computed (the fraction of fat grams and total calories, which does not make sense.) encourage her to find two quantities that are in the same units (i.e., both calories or both grams) to compare in her fraction. Hope this helps.--Dr. Bowers
