Date: Thu Oct 31 05:38:23 PST 2002
Student's Name: Sarah
Answer(or question to Mentor): Dawn, I am working on my project but I have to go to class. Sorry! I am goning to work on it tomorrow. Thanks
~Sarah~
Date: Fri Nov 1 15:14:19 PST 2002
Student's Name: Sarah
Mentor Reply: Hi Sarah,
Thank you for telling me the reason why you were not answering the question on Wednesday. Hope your project is going well.
Hope to hear from you soon. If you need any help with the problem ask--please give me specifics.
Thanks, Dawn
Date: Fri Nov 1 15:40:37 PST 2002
Student's Name: Sarah
Instructor Comments:
Dawn,
Perfect! I agree, giving specifics is much easier when students ask for help. Great job.
Dr. Bowers
Date: Sun Nov 3 18:30:03 PST 2002
Student's Name: Sarah
Answer(or question to Mentor): Dawn,
model 1:--(-)
model 2:-(---)
A)The storm surge went 7 1/2 feet high. I know this because i made a model and (--)- that in parenthasis is 5 ft. so when i did the fourths one there was 3 in parenthasis and since the two equals 5 then 3 equals 7 1/2.
B)2ft and 1/5 high is how much the storm surged in 2002. I know this because I made a model with --- being thirds. When it said 1/3 i covered one --(-) Then I knew there was 5 feet dry. Then for the fourths i did ----. Whn it said 3/4, and how much was dry i covered three -(---) then since there was 2 blocks left on the first one i divided two into 5 because five was how many feet there was left on the first one so I took that for the second one.
Challenge: I will work on this problem on Monday. I don't understand it right now. Thanks!!:)
~Sarah~
Date: Mon Nov 4 11:36:52 PST 2002
Student's Name: Sarah
Mentor Reply: Hi Sarah,
Thank you for telling me the reason why you were not answering the question on Wednesday. Hope your project is going well.
I can see were you came up with the idea that the storm surge is 7 1/2 feet high, but have you considered 7 1/2 feet might be how tall the pole is that is sticking out of the ground. If you consider this you might be able to figure out the hight of the surge in part a and the pole left dry on part b. It can also help you with the problem challenge.
If you need any help with the problem(s), in the future, just ask--please give me specifics.
Have a nice day, Dawn
Date: Tue Nov 5 15:16:56 PST 2002
Student's Name: Sarah
Answer(or question to Mentor): Hey Dawn,
In a matter of fact I do. I need help with the Challenge project, because I don't understand it at all. If you could give me a clue that would be nice.
And Will you give me a hint for part B? Because I thought I got it wrong so if you give me a hint, I might get a better look on the problem.
~Sarah~
Date: Fri Nov 8 11:41:56 PST 2002
Student's Name: Sarah
Mentor Reply: Hi Sarah,
Hope your day is going well.
The 7 1/2 feet is how tall the pole was from the ground to the top. I got this by dividing 5 (from what is dry in 2000, which equals 2/3) by 2 (to find 1/3, which is 1/2 of 2/3), the answer is 2 1/2. When you add 5 and 2 1/2 together you get 7 1/2 feet.
Now to find the storm surge in 2002 you take the height of the pole, which is 7 1/2 feet, and multiply it by 3/4, because you need to know what 3/4 of 7 1/2 feet equals to figure out how many feet the storm surge equals. The answer equals 5 5/8 feet was the height of the storm surge.
For question B, you want to know how much of the pole was dry in 2002, so subtract 7 1/2 by 5 5/8, because you want to know the difference of the pole to how high the storm surge. The answer is 1 7/8 feet that was still dry.
For the challenge problem, the whole pole is 10 feet high. The amount that was stuck in the ground is 4 feet, while 6 feet was out of the ground. The man’s house just barely made it by 3/8 of a foot.
If you have any questions for the next problem just ask specific questions, so I know exactly what you need.
Thanks, Dawn
Date: Fri Nov 15 11:31:28 PST 2002
Student's Name: Sarah
Mentor Reply: Hi Sarah,
I have not heard from you yet. Hope every thing is going fine. If you need any help with this problem just ask. Hope to hear from you soon, Dawn
Date: Fri Nov 15 11:32:52 PST 2002
Student's Name: Sarah
Answer(or question to Mentor): Hey!!! There are 330 calories. I know this because I multyplied 14x9, 36x4, and 15x4. I added them together and I got 330! The daily percent intake is 330%
And 126% is fat. (That is NASTY!)
~Sarah!~
Thanks!! I will work on the Challenge Problem LATA!! CYA!
Date: Fri Nov 15 12:50:29 PST 2002
Student's Name: Sarah
Mentor Reply: Hi Sarah,
You are right there are 330 calories in the cheeseburger. When it comes to the percentage you might need to know where a percentage comes from -- it comes from a fraction. You at least know that there are 330 calories in a cheeseburger and there are 2000 calories Charle eats in a day. Now you want to know the percentage of calories of the cheeseburger to the calories she eats all day. So you will want to make this into a fraction and then divide. Your answer will be a decimal but that is what you want. You then will move the decimal over two spaces to the right and will make it into a percentage sign and that will be the answer in a percent.
The information I gave you in figuring out the percentage for question 1 will be used to find the percentage for question 2. The answer will be different, because you will be using the number of calories in fat, which you have the answer for, and the number of calories in the whole cheeseburger.
Hint for the challenge problem -- start with the bottom of the problem (the 3 nuggets).
If you need any more help just ask.
Thanks, Dawn
Date: Tue Nov 19 16:04:54 PST 2002
Student's Name: Sarah
Mentor Reply: Hi Sarah,
You are right there are 330 calories in the cheeseburger. When it comes to the percentage you might need to know where a percentage comes from -- it comes from a fraction. You at least know that there are 330 calories in a cheeseburger and there are 2000 calories Charle eats in a day. Now you want to know the percentage of calories of the cheeseburger to the calories she eats all day. So you will want to make this into a fraction and then divide. Your answer will be a decimal but that is what you want. You then will move the decimal over two spaces to the right and will make it into a percentage sign and that will be the answer in a percent.
The information I gave you in figuring out the percentage for question 1 will be used to find the percentage for question 2. The answer will be different, because you will be using the number of calories in fat, which you have the answer for, and the number of calories in the whole cheeseburger.
Hint for the challenge problem -- start with the bottom of the problem (the 3 nuggets).
If you need any more help just ask.
Thanks, Dawn
Date: Wed Nov 20 16:09:47 PST 2002
Student's Name: Sarah
Instructor Comments: Dawn,
1. This sentence, 'You at least know that there are 330 calories in a cheeseburger and there are 2000 calories Charle eats in a day. ' could be misconstrued as a bit mean. When you say 'you at least know..' it sounds like you are saying that she doesn't know much, but, at least she knows this... which is not what you mean. Also, the problem does not state that Charle eats 2000 calories in a day, that is the RDA for anyone.
2. The next sentence is also not really mathematically accurate: 'Now you want to know the percentage of calories of the cheeseburger to the calories she eats all day. ' This would be better stated as 'The question asks you to determine what percentage of the RDA caloric intake was taken by the calories in the cheeseburger.'
3. Instead of saying, 'move the decimal over two places,' which would be interpreted as a meaningless rule, can you explain why you do this to convert a decimal to a percent?
Dr. Bowers
