Date: Thu Oct 31 05:38:25 PST 2002
Student's Name: Trey
Answer(or question to Mentor): HEy im still working on it but im almost there i need a little help.
Date: Fri Nov 1 15:05:13 PST 2002
Student's Name: Trey
Mentor Reply: Hi Trey,
Thank you for responding.
I don't know exactly what you need help with, but here is a hint for the problem: You need to find out how many feet of the pole is sticking out of the ground--we know from the problem that 1/3 of the stilt is in the water and that the rest is dry, which is 2/3 of the stilt above ground. Also what we learn from the problem that 5 feet of the stilt is dry which means 2/3 = 5 feet. Now you have to figure out how much 1/3 equals. This will help you with part A.
After you figure how many feet the pole, that is sticking out of the ground, you will want to figure out what 1/4 of the pole is in feet. This will help you with part B.
Thanks, Dawn
Date: Fri Nov 1 15:26:05 PST 2002
Student's Name: Trey
Instructor Comments: Dawn,
Overall, a great response. I think there are a few words that might could make it easier to read. How does this sound?
ONE WAY TO APPROACH THIS PROBLEM IS TO FIGURE OUT THE LENGTH OF THE POLE THAT IS STICKING OUT OF THE GROUND--IF WE FOCUS ON JUST THAT PART, we know from the problem that 1/3 of THIS PART WAS COVERED BY THE STORM SURGE and that the rest is dry. THUS, IF 1/3 IS WET, THEN 2/3 of the stilt IS DRY. Also what we learn from the problem that 5 feet of the stilt is dry. SO, IF 2/3 OF THE POLE REPRESENTS 5 feet, THEN you CAN figure out THE NUMBER OF FEET REPRESENTED BY 1/3 OF THE POLE. NOTE: THIS WILL HELP YOU FIGURE OUT HOW HIGH THE STORM SURGE WAS IN 200O, THEN USE THIS TO ANSWER THE QUESTION REGARDING THE HEIGHT OF THE STORM SURGE IN 2002.
After you figure OUT THE HEIGHT OF the polE (IN FEET) sticking out of the ground, you will want to figure out THE LENGTH OF THE ENTIRE POLE. THE PROBLEM STATES THAT THIS IS 1/4 OF THE WHOLE POLE.
I realized that I "wordsmithed" a lot in your response, but read the two and see if you can see differences. You be the judge of what you finally say!
Dr. Bowers
Date: Mon Nov 4 05:39:12 PST 2002
Student's Name: Trey
Answer(or question to Mentor): Iam working on problem A. I got 7.5 and i got that from multiplying 2.5 times 3. I times that because if you add 1/4 and 3/4 and 1/3 you will end up getting that.
Problem B. It surged 3.2 feet because 3/4 of five feet would be 3.2. So 3.2 is left dry
Date: Mon Nov 4 11:24:37 PST 2002
Student's Name: Trey
Mentor Reply: Hi Trey,
I see you are on the right track, but I need to know more specifically what the 7.5 is talking about, for example, is it the hight of the storm surge or the pole that is sticking out of the ground. Also I would like to know why you add 1/4, 3/4, and 1/3.
When you figure out how tall the pole is you might be able to figure the answers to questions a and b, even the challenge problem.
If you have any questions please ask very specific ones.
Thanks, Dawn
Date: Thu Nov 7 05:29:13 PST 2002
Student's Name: Trey
Answer(or question to Mentor): Im not sure i was confused on this question so i drew a picture and it came out that way.
Date: Fri Nov 8 11:39:24 PST 2002
Student's Name: Trey
Mentor Reply: Hi Trey,
Hope your day is going well.
The 7 1/2 feet is how tall the pole was from the ground to the top. I got this by dividing 5 (from what is dry in 2000, which equals 2/3) by 2 (to find 1/3, which is 1/2 of 2/3), the answer is 2 1/2. When you add 5 and 2 1/2 together you get 7 1/2 feet.
Now to find the storm surge in 2002 you take the height of the pole, which is 7 1/2 feet, and multiply it by 3/4, because you need to know what 3/4 of 7 1/2 feet equals to figure out how many feet the storm surge equals. The answer equals 5 5/8 feet was the height of the storm surge.
For question B, you want to know how much of the pole was dry in 2002, so subtract 7 1/2 by 5 5/8, because you want to know the difference of the pole to how high the storm surge. The answer is 1 7/8 feet that was still dry.
For the challenge problem, the whole pole is 10 feet high. The amount that was stuck in the ground is 4 feet, while 6 feet was out of the ground. The man’s house just barely made it by 3/8 of a foot.
If you have any questions for the next problem just ask specific questions, so I know exactly what you need.
Thanks, Dawn
Date: Wed Nov 13 12:59:38 PST 2002
Student's Name: Trey
Answer(or question to Mentor): Hey i fifured out i just adend all the calories
and followed the directions it was the easyiest one there was thank
i will give u a more info tommorow but i am in a hurry
Date: Fri Nov 15 12:34:54 PST 2002
Student's Name: Trey
Mentor Reply: Hi Trey,
Hope your day is going well. When you do get the chance to answer the questions can you please give me a lot of information on how you got to the answer. I would really appreciate it very much. I notice that you know that you have to add, but there is multiplying and some dividing. If you need any help trying to figure out were please ask -- specific questions.
Dawn
Date: Tue Nov 19 16:00:46 PST 2002
Student's Name: Trey
Mentor Reply: Hi Trey,
Hope your day is going well. When you do get the chance to answer the questions can you please give me a lot of information on how you got to the answer. I would really appreciate it very much. I notice that you know that you have to add, but there is multiplying and some dividing. If you need any help trying to figure out were please ask -- specific questions.
Dawn
Date: Wed Nov 20 15:59:44 PST 2002
Student's Name: Trey
Instructor Comments: Dawn,
I would open with something like, 'Thanks for sending your initial thoughts on the problem.' Also, instead of asking for 'lots of information' I think it would be better if you could ask him more directly to give 'a detailed explanation of what you added, multiplied, divided, etc. and why you did these operations'. The goal here is not simply for the students to write a lot, but, in fact, to write concisely!
Dr. Bowers
